Calculate the molar concentration of OH− ions in a 0.069 M solution of ethylamine (C2H5NH2 ; Kb=6.4×10−4
Calculate the molar concentration of OH− ions in a 0.069 M solution of ethylamine (C2H5NH2 ;...
16)Calculate the molar concentration of OH− ions in a 0.074 M solution of ethylamine (C2H5NH2 ; Kb=6.4×10−4 ).
15. Calculate the molar concentration of OH− ions in a 0.074 M solution of ethylamine (C2H5NH2 ; Kb=6.4×10−4 ).
Calculate the pH of this solution molar concentration of OH− ions in a 0.085 M solution of ethylamine (C2H5NH2; Kb=6.4×10−4). [OH−] [OH−] = 7.1×10−3 M Calculate the pH of this solution. Express your answer to two decimal places.
Calculate the molar concentration of OH-ions in a 0.084 M solution of ethylamine (C2H, NH2 ; Kb-6.4 × 10-4). Express your answer to two significant figures. OH] Previous Answers Request Answer
Find the [OH−] of a 0.44 M ethylamine (C2H5NH2) solution. (The value of Kb for ethylamine (C2H5NH2) is 5.6×10−4.) Express your answer to two significant figures and include the appropriate units.
a. The hydroxide ion concentration, [OH-], of an aqueous solution of 0.331 M ethylamine (a weak base with the formula C2H5NH2) , Kb = 4.3×10-4, is: [OH-] = ___________ b. The hydronium ion concentration of an aqueous solution of 0.331 M codeine (a weak base with the formula C18H21O3N) is ... [H3O+] = __________
Part A Calculate the molar concentration of OH ions in a 0.555 M solution of hypobromite ion (BrO; Kb 4.0 x 10-) Express the molarity to two significant digits. V ΑΣφ ? [OH М What is the pH of this solution? Express the pH to two decimal places. VAD ΑΣφ ? pH=
Find the pH of the solution obtained when 32 mL of 0.087 M ethylamine, C2H5NH2, is titrated to the equivalence point with 0.15 M HCl. The value of Kb for ethylamine is 4.7 x 10-4. (in 3 s.f.)
Determine the hydronium ion concentration during the titration of 6.72 mL of 0.700 M ethylamine (C2H5NH2. Kb = 4.30x10-4) by 19.4 ml of 0.700 M HBr.
Calculate the pH of a buffer solution that is 0.116 M in C2H5NH2 (ethylamine) and 0.403 M in C2H5NH3Cl.