A)
BrO- dissociates as:
BrO- +H2O -----> HBrO + OH-
0.555 0 0
0.555-x x x
Kb = [HBrO][OH-]/[BrO-]
Kb = x*x/(c-x)
Assuming x can be ignored as compared to c
So, above expression becomes
Kb = x*x/(c)
so, x = sqrt (Kb*c)
x = sqrt ((4*10^-6)*0.555) = 1.49*10^-3
since c is much greater than x, our assumption is correct
so, x = 1.49*10^-3 M
So, [OH-] = x = 1.49*10^-3 M
Answer: 1.5*10^-3 M
B)
use:
pOH = -log [OH-]
= -log (1.49*10^-3)
= 2.8268
use:
PH = 14 - pOH
= 14 - 2.8268
= 11.1732
Answer: 11.17
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