the air in a 5.000-L tank has a pressure of 1.20 atm. What is the final pressure, in atmospheres, when the air is placed in tanks that have the following volumes, if there is not change in temperature and amount of gas? a) 1.00L b) 2500.mL c)750.mL d) 8.00L
a.
intial final
P1 = 1.2atm P2 =
V1 = 5L V2 = 1L
P1V1 = P2V2
P2 = P1V1/V2
= 1.2*5/1 = 6atm>>>>>>>>>answer
b.
intial final
P1 = 1.2atm P2 =
V1 = 5L V2 = 2500ml = 2.5L
P1V1 = P2V2
P2 = P1V1/V2
= 1.2*5/2.5 = 2.4atm
c.
intial final
P1 = 1.2atm P2 =
V1 = 5L V2 = 750ml = 0.75L
P1V1 = P2V2
P2 = P1V1/V2
= 1.2*5/0.75 = 8atm
d.
intial final
P1 = 1.2atm P2 =
V1 = 5L V2 = 8L
P1V1 = P2V2
P2 = P1V1/V2
= 1.2*5/8 = 0.75atm
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