Question

Find sin , cos , and tan - O A. sino= _ . cosO=- , tan 0= - 13 O B. sino= - ], COSO = 3, tan o=1/3 o c. sino=- , coso - ., tan og OD. sino - 13. COSO = 1, tan 0=13

Answer 1

here, 8 = 149**** Date 18=1] Primery (2) Now smo- y = -1 4 = 1 coso = x = 3 = - 13 tano = y = (-214-2) = 1 = 1 So, Ans is [c] sim (510) Esin Carl +150°) = Sim (150) - Sin (211+0) = Gino sm (anto = sin(T-30). = Sim 30° • sim (1-0) = sino. ☺ so Ans is [c] ton (1176) = tan (37 + 27) 1 = tan (ar) = tan (120°) . = tan (180° -60°) = -tan (60) = -13. So, Ans is [D]. tan (canti)tto)= tand. stan (T1-0) = - tano.

@ f(10) = f (40) Hier_10+{pxn) = 40_ __with o is the period of function suppose oxn) = 40 with ñ being cuinteger Now checking for all options provided p=15_ n=a i integer .. 15 is a can be its period . 10+15n = 40 10+60=40 =5 p=5 10+5na40 n = 6 p=4 10+4 n=40 - n = 7,5 not integer us can't be period 3 ans is [DJ. A explained in sino = J(0.3)2+(0.6)2 = 1 L P is on the unit urcle hence this problem is very , sino = -- Val- summilar to o - 0.6 coso = 2 = 0.8 So Ans is [.. tamo = y = 0.6 0.75 Dib