Question

package exampleassignment;

import java.util.Arrays;

import stdlib.*;

public class assignment {

       /**

       * valRange returns the difference between the maximum and minimum values in the

       * array; Max-Min. Precondition: the array is nonempty. Your solution must go

       * through the array at most once.

       *

       * Here are some examples (using "==" informally):

       *

       * <pre>

       *    0 == valRange (new double[] { -7 })

       *    10 == valRange (new double[] { 1, 7, 8, 11 })

       *    10 == valRange (new double[] { 11, 7, 8, 1 })

       *    18 == valRange (new double[] { 1, -4, -7, 7, 8, 11 })

       *    24 == valRange (new double[] { -13, -4, -7, 7, 8, 11 })

       *

       * you should replace the line of code

       * labeled TODO with code that achieves the above specification

       * </pre>

       */

       public static double valRange(double[] list) {

             return -1; // TODO 1: fix this code

       }

       /**

       * posOfLargestElementLtOeT returns the position of the largest element in the

       * array that is less than or equal to the limit parameter if all values are

       * greater than limit, return -1;

       *

       * Precondition: the array is nonempty and all elements are unique. Your

       * solution must go through the array exactly once.

       *

       * <pre>

       *   0 == posOfLargestElementLtOeT(3, new double[] { -7 })                      // value:-7 is in pos 0

       *   5 == posOfLargestElementLtOeT(3, new double[] { 11, -4, -7, 7, 8, 1 }),    // value:1 is in pos 5

       * -1 == posOfLargestElementLtOeT(-7, new double[] { 1, -4, -5, 7, 8, 11 }),   // all elements are > -7

       *

       * The code below is a stub version, you should replace the line of code

       * labeled TODO with code that achieves the above specification

       * </pre>

       */

       public static int posOfLargestElementLtOeT(double limit, double[] list) {

             return -2; // TODO 2: fix this

       }

Answer 1

import java.util.Arrays;

public class Assignment {
   public static double valRange(double[] list)
   {
       // if only one elementt in list
       if (list.length <= 1) {
           return 0;
       }
       else
       {
           // consider 1 element as both max and min
           double min = list[0];
           double max = list[0];

           for (int i = 1; i < list.length ; ++i )
           {
               // if new max found update max
               if(list[i] > max)
               {
                   max = list[i];
               }
               // if new min found update min
               else if (list[i] < min)
               {
                   min = list[i];
               }
           }
          
           return (max - min);
       }
   }

   public static int posOfLargestElementLtOeT(double limit, double[] list)
   {
       // consider initial index is -1
       int lastIndex = -1;
       for (int i = 0; i < list.length ; ++i)
       {
           // if less number found then update index
           if(list[i] < limit)
           {
               lastIndex = i;
           }
       }
       // return index
       return lastIndex;
   }

   public static void main(String[] args)
   {
       System.out.println("Value of valRange");
       System.out.println(valRange(new double[] { -7 }));
       System.out.println(valRange(new double[] { 1, 7, 8, 11 }));
       System.out.println(valRange(new double[] { 11, 7, 8, 1 }));
       System.out.println(valRange(new double[] { 1, -4, -7, 7, 8, 11 }));
       System.out.println(valRange(new double[] { -13, -4, -7, 7, 8, 11 }));

       System.out.println("\nValue of posOfLargestElementLtOeT");
       System.out.println(posOfLargestElementLtOeT(3, new double[] { -7 }));
       System.out.println(posOfLargestElementLtOeT(3, new double[] { 11, -4, -7, 7, 8, 1 }));
       System.out.println(posOfLargestElementLtOeT(-7, new double[] { 1, -4, -5, 7, 8, 11 }));
   }
}

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11 A en TUE ULL U -/Desktop/Assignment.java - Sublime Text (UNREGISTERED) Project Preferences Help Edit File Selection Find View Goto Tools x X b sicOper.py Assignment.java StringReverse.java X office@Angel: -/Desktop - O File Edit View Search Terminal Help office@Angel:-/Desktops javac Assignment.java office@Angel:-/Desktop$ java Assignment Value of valRange 0.0 10.0 10.0 18.0 24.0 public static int posOfLargestElementLtoeT(double limit, doubled list), // consider initial index is -1 int lastIndex = -1; for (int i = 0; i < list.length; ++i), value of posofLargestElementitet // if less number found then update index if(list[i] < limit) lastIndex = i; -1 office@Angel:-/Desktops | // return index return lastIndex; public static void main(String[] args), System.out.println("Value of valRange"); System.out.println(valRange(new double() { -7 })); System.out.println(valRange(new double() { 1, 7, 8, 11 })); System.out.println(valRange(new double[] { 11, 7, 8, i })); System.out.println(valRange(new double[] { 1, -4, -7, 7, 8, 11 })); System.out.println(valRange(new double[] { -13, -4, -7, 7, 8, 11 })); System.out.println("\nValue of posofLargestElementLtoeT"); System.out.println(posofLargestElementltoeT(3, new double() { -7 })); System.out.println(posoflargestElementLtOeT(3, new double[] { 11, -4, -7, 7, 8, i })); System.out.println(posoflargestElementLtoeT(-7, new double() { 1, -4, 5, 7, 8, 11 })); 64 }