Question

(17%) Problem 6: Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1350 kg and is approaching at 6.5 m/s due south. The second car has a mass of 650 kg and is approaching at 19.5 m/s due west. 33% Part (a) Calculate the magnitude of the final velocity, in meters per second, of the cars. Grade Summary Deductions Potential 100 ( HOME sin() cos() tan() cotan() asin() acos atan acotan) sinh). cosh() tanh) | cotanh). O Degrees O Radians Submissions Attempts remaining 2% per attempt) detailed view + 7 8 9 56 1 2 3 - 0 . BACKSPACE 1 give up! END CLEAR V Submit Hint Hints: 0% deduction per hint. Hints remaining: 2 Feedback: 0% deduction per feedback. 33% Part (b) Calculate the direction of the final velocity, in degrees south of west, of the cars. 33% Part (c) What is the change in kinetic energy, in joules, for the collision? (This energy goes into deformation of the cars.)

Answer 1

A)

Tan(theta) = m1 v1/m2v2

Tan(theta) = (1350 x 6.5)/(650 x 19.5)

Theta = 34.7°  (Answer for part (b))

Velocity, v = (1350 x 6.5)/((1350 + 650) sin(34.7) = 7.71 m/s   (Answer for part (A))

C)

E = (0.5 x (1350 + 650) x 7.71^2) - (0.5 x 1350 x 6.5^2) - (0.5 x 650 x 19.5^2) = -9.27 x 10^4 J

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