Question

Consider the experimental results for the following randomized block design. Make the calculations necessary to set up the analysis of variance table. Treatments C B A 1 10 9 8 2 13 6 5 Blocks 3 18 15 14 4 20 18 18 7 8 0.05 to test for any significant differences. Use a State the null and alternative hypotheses. Ho: At least two of the population means are equal Ha At least two of the population means are different. о на МА - Ив - Ас H Not all the population means are equal. о на МА + Мв + Mс Наi МА 3 Мв 3D Мс О на: МА 3D ив 3D Мс На: НА + Из + нс OHo: Not all the population means are equal. На: НА 3 Мв 3 Мс

Answer 1

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SAS Proce *Program 1 X CODE OUTPUT DATA LOG RESULTS B ра 1 data new; 2 input treatment $ block value; 3 cards 4 A 1 10 5 A 2 13 6 A 3 18 7 A 4 20 8 A 5 8 9 B 1 9 10 В 2 6 11 B 3 15 12 B 4 18 13 В 5 7 15 C 2 5 16 C 3 14 17 C 4 18 18 C 5 8 19 20 run 21 proc print data=new; 22 run; 23 proc glm data=new; 24 class block treatment; 25 model value = treatment block; 26 random block; run e 2

The GLM Procedure Dependent Variable: value Pr> F Mean Square | F Value Sum of Squares DF Source 0.0002 20.67 55.8000000 334.8000000 6 Model 2.7000000 21.6000000 8 Error 356 4000000 14 Corected Total value Mean Root MSE Coeff Var R.Square 11.80000 1.643168 13 92515 0 939394 Pr> F F Value Mean Square Type I SS DF Source 0.0298 5.63 15 2000000 30 4000000 treatment <0001 28.19 76 1000000 304 4000000 4 block Pr F F Value Mean Square TypeI SS DF Source 0.0298 5.63 15 2000000 30 4000000 treatment <0001 28 19 76 1000000 304.4000000 block Interaction Plot for value

RGui (32 bi View Misc Packages Wind- File Edit R R Console qf (0.95,2,9) [1] 4.45897 ***