Question

using C++

Write a program that:
a) Inputs an integer n from the keyboard where n<=100. If n is out of range then
print out an error message and ask for another input. This process repeats until a
valid value for n is obtained.
b) Inputs two 1D arrays of doubles A and B (of size n) from the keyboard.
c) Inputs an integer k (from 1 to 3) from the keyboard.
d) If k = 1 then it calculates the average value of A[i] and prints it to the screen.
e) If k = 2 then it calculates the minimum value of B[i] and prints it to the screen.
f) If k = 3 then it calculates the dot product of A and B and prints the result to the
screen.
g) If k is out of range then the program prints out an error message and terminates
the program.
h) Parts c) to g) repeat until every valid value of k (ie menu item) has been selected
at least once (or part g terminates the program). If you don’t know how to do this
part you can just assume parts c) to g) repeat indefinitely.

Answer 1

Sol.

Below is implemented according to the parts of the quetion.

#include<bits/stdc++.h>
using namespace std;

void avg(double * A, double * B, int n){
double sum=0;
for(int i=0;i<n;i++)
sum+=A[i];
cout<<"Average value of A is: "<<sum/n<<endl;
}

void mini(double * B , int n){
double *m = min_element(B, B+n);
cout<<"Minimum value of B is: "<<*m<<endl;
}

void dot(double *A, double *B, int n){
double sum=0;
for(int i=0;i<n;i++){
sum+=A[i]*B[i];
}
cout<<"Dot product is: "<<sum<<endl;
}

int main(){
int n,k,a=100;
while(a){
cout<<"Enter the value between 0 to 100: "<<endl;
cin>>n;
if(n>100 || n<0)
continue;
double A[n], B[n];
cout<<"Enter value for array A"<<endl;
for(int i=0;i<n;i++)
cin>>A[i];
cout<<"Enter value for array B"<<endl;
for(int i=0;i<n;i++)
cin>>B[i];
int k = 0;
cout<<"Enter value of k between 1 to 3"<<endl;
cin>>k;
if(k>3 || k<1){
cout<<"Entered K value was not in range"<<endl;
break;
}
if(k==1)
avg(A,B,n);
if(k==2)
mini(B,n);
if(k==3)
dot(A,B,n);
  
a--;
}

return 0;
}

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