Question

Incorrect Question 9 0/1 pts A water sample is contaminated by benzene at a concentration of 40 mg/L. If you have only 20 g of activated carbon, what is the volume of water (in mL) that can be treated to the final concentration of 5 mg/L. The Freundlich isotherm coefficients are K = 5 and n = 2.5 for concentrations in g/L. 205 mL 343 mL 292 mL 505 mL

Answer 1

Initial concentration C_o= 40mg/L

Final concentration C_e = 5 mg/L

Mass of adsorbant M = 20g

K = 5

n = 2.5

Mass of material adsorbed per unit mass of adsorbant

q_e = K C_e^1/n

^{= 5 (5/1000)^(1/2.5)}

^{= 0.6}

^q_e = -

) (Co- Ce x

0.6 = -

x (5 40)/1000 20

Volume, V = 342.86 mL

Hence Answer is V = 343 mL