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Assume currents l_2 and I_3, flow in the directions shown. Draw current l_2 through the middle...
We name currents I_1, I_2, and I_3 as shown. From Kirchhoff's current rule, I_3 = I_1...
We name currents I_1, I_2, and I_3 as shown. From Kirchhoff's current rule, I_3 = I_1 + I_2. Applying Kirchhoff's voltage rule to the loop containing I_2 and I_3. 12.0 V - (4.00)I_3 - (6.00)I_2 - 4.00 V = 0 8.00 = (4.00)I_3 + (6.00)I_2 Applying Kirchhoff's voltage rule to the loop containing I_1 and I_2. -(6.00)I_2 - 4.00 V + (8.00)I_1 = 0 (8.00)_I_1 = 4.00 + (6.00)I_2. Solving the above linear system, we proceed to the pair of...
1) In the circuit below the currents are named A, and lc The current direction is determined by the source (out of positive terminal) in the middle and right branches and is clockwise in the left bra...
1) In the circuit below the currents are named A, and lc The current direction is determined by the source (out of positive terminal) in the middle and right branches and is clockwise in the left branch · IA flows through R2 and R1 Is flows through R4 and Vb cflows through R3, Vc AB R2 R3 R4 R1 Vb a) Draw the circuit and show the 3 currents described above, including arrows showing the current direction. Show the voltage...
I need aome help with this part of my lab. thank you! Kirchoff's Laws 4. Now...
I need aome help with this part of my lab. thank you!
Kirchoff's Laws 4. Now click on this link, which is another circuit I modified and created for this lab: http://tinyurl.com/y8toda84 A. Do not Click run/Stop. This is a circuit that has elements that are neither series nor parallel, as well as multiple voltage sources. The best way for us to analyze this circuit is to use Kirchoff's laws. From the text here are Kirchoff's laws: 1) The sum...
I only need help with the discussion there are many info that you do not need put I put just in ...
I only need help with the discussion
there are many info that you do not need put I put just in
case as well as my data table.
please do it as soon as u can
Meauements ODeit1 Check2 Meaurements Checi3 Ced Check5 Check6 Measurements Check7 heck8 4058 33 536 1502 1035 979 119478 041 1.0319|0.554972| 64261| 153|15542033681 995781 5266566 1578807 298h 1631 119 1209430016 079096812 0.418135246 0,00032665 011890:004668155728441 0293237 1.291809502 1.22833 1.28 1952 -1116 4281 140616885511984206317 3346 8162 0.78...
We name currents I_1, I_2, and I_3 as shown. From Kirchhoff's current rule, I_3 = I_1 + I_2. Applying Kirchhoff's voltage rule to the loop containing I_2 and I_3. 12.0 V - (4.00)I_3 - (6.00)I_2 - 4.00 V = 0 8.00 = (4.00)I_3 + (6.00)I_2 Applying Kirchhoff's voltage rule to the loop containing I_1 and I_2. -(6.00)I_2 - 4.00 V + (8.00)I_1 = 0 (8.00)_I_1 = 4.00 + (6.00)I_2. Solving the above linear system, we proceed to the pair of...
1) In the circuit below the currents are named A, and lc The current direction is determined by the source (out of positive terminal) in the middle and right branches and is clockwise in the left branch · IA flows through R2 and R1 Is flows through R4 and Vb cflows through R3, Vc AB R2 R3 R4 R1 Vb a) Draw the circuit and show the 3 currents described above, including arrows showing the current direction. Show the voltage...
I need aome help with this part of my lab. thank you!
Kirchoff's Laws 4. Now click on this link, which is another circuit I modified and created for this lab: http://tinyurl.com/y8toda84 A. Do not Click run/Stop. This is a circuit that has elements that are neither series nor parallel, as well as multiple voltage sources. The best way for us to analyze this circuit is to use Kirchoff's laws. From the text here are Kirchoff's laws: 1) The sum...
I only need help with the discussion
there are many info that you do not need put I put just in
case as well as my data table.
please do it as soon as u can
Meauements ODeit1 Check2 Meaurements Checi3 Ced Check5 Check6 Measurements Check7 heck8 4058 33 536 1502 1035 979 119478 041 1.0319|0.554972| 64261| 153|15542033681 995781 5266566 1578807 298h 1631 119 1209430016 079096812 0.418135246 0,00032665 011890:004668155728441 0293237 1.291809502 1.22833 1.28 1952 -1116 4281 140616885511984206317 3346 8162 0.78...
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