Question

103, 10 Answer

At one instant in time, the situation shown in the figure happens. A 7.01 kg particle P has a position vector r of magnitude 3.19 m and angle θ₁ = 45° and a velocity vector v of magnitude 1.37 m/s and angle θ₂ = 30°. Force F of magnitude 9.13 N and angle θ₃ = 30° acts on P. All three vectors lie in the xy-plane.

About the origin, what is the angular momentum of P, in kg•m²/s?

Determine the direction with a + or - sign (for a +z or -z direction, counterclockwise or clockwise, respectively).

Answer 1

Direction of angular momentum is same as direction of r x v. To get direction of r x v , move fingers of right hand from direction of r to direction of v through smaller angle, ( pi - theta2 ) in this case, thumb points toward direction of r x v or angular momentum.

V e v 5 > ANGULAR MOMENTUM ABOUT ORIGIN nr I ELE sin o MASS POSITION VECTOR ū VELOCITY VECTOR r - POSITION VECTOR MAGNITUDE VELOCITY VECTOR MAGNITUDE o - ANGLE BETWEEN Į & v 2 L L = mrv Sin (T-02) = meu sin (O₂) so I V REDMI NOTE 8 AI QUAD CAMERA (7.01kg) (3.19 m) (1:37 m/s) fun (30°) 15.3 kg m/ set

Hence direction of angular momentum is +ve or counterclockwise.