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At the instant shown in the figure, a 2.0 kg particle p has a position vector...

At the instant shown in the figure, a 2.0 kg particle p has a position vector of magnitude 3.0 m and angle theta1 = 45

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Answer #1

torque T = r*F*sin(45-30) = 3*7.3*sin 15 = 5.668 Nm

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