From the given question,
11. Initial speed(u)=49 m/s
Acceleration(a)=9.8 m/s^2
Time(t)=1 sec
Final velocity(v) = u+at
=49+(9.8)(1)
=58.8 m/s
12.Distance travelled in 1 sec(s)= ut +(1/2)(a)(t^2)
=(49)(1)+(1/2)(9.8)(1^2)
=58.8 m
13. As the initial vertical velocity of both bullets is same ( 0 m/s), they both will strike at same instant.
14. Initial vertical velocity(u)= 0 m/s
Acceleration due to gravity(a)=9.8 m/s^2
Time= 3 s
Distance travelled(s)=ut+(1/2)at^2
=(0)(3)+(1/2)(9.8)(3^2)
=44.1m
Horizontal distance stone hits= horizontal velocity*time
=20*3
=60 m
11. Suppose you throw a ball vertically downward with a speed of 49 m/s What would...
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