Answer:
a)
Given,
Mean = 15.92
Standard deviation = 8.301
Sample = 13
degree of freedom = n - 1 = 13 - 1 = 12
alpha = 0.02
t = 2.680997 = 2.681
Here we use t distribution
b)
98% CI = xbar +/- t*s/sqrt(n)
substitute values
= 15.92 +/- 2.681*8.301/sqrt(13)
= 15.92 +/- 6.1724
= (9.7476 , 22.0924)
c)
98% , 2%
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