Question

The current in the triangular wire loop is I = 5.0 A, as shown in the figure. The loop is in a flat magnetic field B = (3.0T) (a) Calculate the magnetic moment of the current loop and, with it, calculate the torque affecting on the loop In what direction does this torque tend to turn the loop? (b) Calculate the magnetic forces affecting on the sides of the triangle and, with their help, calculate the magnetic torque. (Can you get the same result this way?) Answer: 3.6 Nm y/cm 60 x/cm 80

Answer 1

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Bisms 1 B a. t = 5 x Bt where m= i bi & Exã . 0.8m a m= 5* I (0.8) (0.6)=1.2 Am² I so E = mB= 10243 N-m = 3.6 Nm I b Force on length AB F = I J de x Š Ide = 110.63+10.892 - 1 F = 5x 3 x sin (0) 0=x+go? F = ls. Sin (12687 X = Jan 10.b) F = 12N 4-36.67° force on OB F = 580-883 N Coogle = gi F = /2N Singo=1) force on OA F = 0 (angle o See the torque about point a (midpoint of OB) where d = c.D = F. d 12 XCCO) - 3.6N Il Sin 820)