Question

4) A long straight wire carries current i = 2.0 A. A triangular loop (w = 0.050 m and t = 0.100 m) also carries the same current and is located at distance x = 0.025 m from the straight wire as shown. Recall that the magnetic field due to a long straight wire is given by B Ho 21 4r where r is the perpendicular distance from the wire. Note: Ho/472 = 1 x 10-?T.m/A. a) Determine the magnitude and direction of the magnetic force acting on the parallel piece of the triangular loop due to the long straight wire. b) Set up, then evaluate the definite integral that will allow you to calculate the magnitude of the magnetic force acting on the perpendicular piece of the triangular loop due to the long straight wire.

Answer 1

I current carrying wires in same direction attract each other in presence of magnetic field of other wire 14 xx Magnetic field on the location of triangle length ľ Ho I (-E) B Zax 3.2 X10 TH 3.2 x 10 1166 N F = I êx B F-I l ( I) (Êx (-1)) [as exc-t) оху gx 0.1x2x107 0.025 magnitude Direction - towards long wire B = tho I (-Ê die - Idex B अy I(dy tŷi) F (6) I ly XB dÅ dy as Egixch 24w I I dy (ha a F = to I2 [lny zato Mo I² [en [ln (24) ZA magnitude=F= 3.944 xrott 3.944 x 10*t, Direction= +Xaxis

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