we are given two points as
Firstly, we will find slope
now, we can use point slope form of line
now, we can solve for y
...........Answer
8. (0/5 Points] DETAILS PREVIOUS ANSWERS LARCALCET7 1.2.046. Find an equation of the line that passes...
Viewing Saved Work Revert to Last Response 13. DETAILS LARCALCET7 3.2.059. Consider the given function and point. Rex) = -5 + 9x2 - 4, (1, 0) (a) Find an equation of the tangent line to the graph of the function at the given point. (b) Use a graphing utility to graph the function and its tangent line at the point. Use the tangent feature of the graphing у -2 MacBook Air esc 80 DOO 004 4 11 FS л :...
-/2 POINTS SCALC8 1.4.JIT.003.MI. Find the slope-intercept form of the equation of the line passing through the given points. (1, 1), (5,- Sketch the line. Graph Layers After you add an object to the graph you can use Graph Layers to view and edit its properties. MOSO WebAssign Graphing Tool tead Help? Red Watch Master Talk to Tutor
2. [0/5 Points] DETAILS PREVIOUS ANSWERS LARCALCET7 5.1.018. Find the indefinite integral and check your result by differentiation. (Use C for the constant of integration.) 1 dx |(vx+ 5*) )(2x+1)+ Need Help? Read it Talk to a Tutor 3. [-15 Points) DETAILS LARCALCET7 5.1.038.MI. Find the particular solution of the differential equation that satisfies the initial condition(s). g'(x) = 2x2, g(-1) = 5 g(x) - Need Help? Read It Master it Talk to a Tutor Submit Answer 4. [-15 Points)...
4. [3/8 Points) DETAILS PREVIOUS ANSWERS SCALCCC4 9.5.013. Consider the line that passes through the point and is parallel to the given vector. (4, -3,6) < 1, 2, -3> (a) Find symmetric equations for the line. 2-6 -(x-4)= 2 3 y +3 (b) Find the points in which the line intersects the coordinate planes. (5 X IX 0) (0,9 X -6 (4 x 0, 4 X) 1 Consider the line that passes through the point and is perpendicular to the...
1. Show the points used as well. 2. Find the slope-intercept form of the equation of the line passing through the given points. (1, 1), (5,- ) 7 y = -.X + 20 27 20 Sketch the line. 1 10 9 Graph Layers Clear All 8 Point 1 7 Delete 6 P1 Fill Point 2 11. P1 (3 -2/5 -10-9-8-7-6 -5 -4 -3 -2 -1 . 6 8 9 10 -1 -2 No Solution Point 3 -3 -5 P1 1.35...
Problem 4: (a) (5 points) Find the equation for the line that passes through the points (-4,-2) and (8, 1). Write your equation in se form, slope-intercept form, or point- slope form. (Extra Credit: Write the equation for the line in all three forms) (b) (5 points) Graph the line. Problem 5: (10 points) Find the equation for the line passing through the point (3.2) and perpendicular to the line y = ',x + 7. The the line Problem 6:...
4. [0/8 Points) DETAILS PREVIOUS ANSWERS LARCALC11 2.5.045. Use implicit differentiation to find an equation of the tangent line to the ellipse at the given point. x2 y2 = 3, (5,-2) + 10 8 y = 2 X
Question1 Find the slope of the line that passes through the given points. (4, -5) and (7, -7) Select the correct choice below and, if necessary, fill in the answer box within your choice. A. The slope is (Type an integer or a simplified fraction.) B. The slope is undefined. Question 2 Graph the linear equation and find its slope. AY 10 x= -5 8 Use the graphing tool to graph the linear equation. 6 Click to 4 enlarge graph...
Q4. (5 points). Find the equation of the plane that passes through the line of intersection of the two planes x - 2y = 3 and y- z = 0 and parallel to the line x = y - 1 = 2+1 Q5. (4 points). Find the distance from the point A(1,2,3) and the line 2+1 y-1 2 Q6. (4 points). Give the name and sketch the surface whose equation is given by x2 + 2y2 – 12y – z...
o1 points 1 Previous Answors LarPCalc8 10.2.012. 1. Describe in words how a plane could intersect with the double-napped cone shown to form the conic section. (Select all that apply.) Hyperbola e The plane intersects both the top and bottom of a double-napped cone. The plane is perpendicular to the axis of the cone. e The plane intersects only the top or bottom half of a double-napped cone. The plane is parallel to the axis of the cone. The plane...