Question

write it in matlab language

Question No 4 6 Marks The surface area and volume of the shown ring-shaped mechanical part are calculated respectively as follows: A =rd (2k +d) V = *d? (2R +d) Write a user defined function that computes surface area (A) and volume (V) of this ring from the arguments d and R. Suppose that is constrained to be 15 in, greater than d. Write a script file that uses your function to plot A and V versus d for 0.5 <d<3

Answer 1

Question 4

SOURCE CODE IN MATLAB:

areaVolume.m

function [A, V]=areaVolume(R, d)
%calculating area A and volume V
A=pi*pi*d*(2*R+d);
V=0.25*pi*pi*d*d*(2*R+d);
end

areaVolumeGraph.m

D=0.5 : 0.1 : 3; %setting diameter d from 0.5 to 3
A=[];
V=[];
k=1;
%finding area and volume
for d=D
R=d+15;
[A(k), V(k)]=areaVolume(R, d);
k+=1;
end
%plotting results
plot(D, A, D, V), title("Area and Volume vs Diameter"), legend("Area", "Volume"), xlabel("d --->"), ylabel("Area/Volume --->");

OUTPUT:

octave:5> source("areaVolumeGraph.m") Area and Volume vs Diameter 1200 T T Volume Area/Volume --> 1 1.5 2 2.5

Question 3

SOURCE CODE IN MATLAB:

%1
A=[13 -10 15; 19 14 -11; -17 18 24; 12 -31 16]
B=[-10 8 11; 14 11 -8; 13 -14 18; 9 23 -12]

%2
sum1=sum(A(:, 2))

%3
prod1=prod(B(3, :))

%4
colProd=A(:, 1).*B(:, 2)

%5
colProdSum=sum(A(2, :).*B(4, :))

%6
colProdMax=max(A(:, 2).*B(:, 1))

OUTPUT:

octave: 13> source ("matrixops.m") A = 13 -10 15 1914 -11 - 17 18 24 12 -31 16 - 10 14 13 9 8 11 11 - 8 -14 18 23 -12 suml = -9 prodl = -3276 colProd = 104 209 238 276 colProdSum = 625 col ProdMax = 234

Regards!