A 1840 kg car has just passed a diner. The closest the car came to the diner was R = 24.5 m, but the car has driven another x = 38.7 m in the 2.45 s elapsed since then. If the car travels at constant speed, what is the current magnitude of the angular momentum of the car about the diner?
here,
mass of the car , m = 1840 kg
x = 38.7 m , t = 2.45 s
speed of car , v= x/t
v = 15.8 m/s
R = 24.5 m
the current magnitude of the angular momentum of the car about the diner , L = m * v * r
L = 1840 * 15.8 * 24.5
L = 7.12 * 10^5 kg.m^2/s
the current magnitude of the angular momentum of the car about the diner is 7.12 * 10^5 kg.m^2/s
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A counterweight of mass m = 4.90 kg is attached to a
light cord that is wound around a pulley as shown in the figure
below. The pulley is a thin hoop of radius R = 7.00 cm and
mass M = 2.50 kg. The spokes have negligible mass.
(a) What is the net torque on the system about the axle of the
pulley?
magnitude
direction
to the right along the axis of rotation to the left along the
axis...