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Question 2 (10Pts) A formula 1 car is driving on a straight line with v, = 24 m/s and it decelerates with a negative accelera

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a ) a=- 2:3 -2.3 v Vo = 24 mis a = du at a = du xds ds dt where ds = displacemca a = v du Ts vdu ds - 24 =-2.312 ds = do -2.30 3/2 - 2.3 10) 3/2 24 s= (23)* [(a) no] s= 2x1 x(524) 3 2.3 * 3:3 s=34 meter s=34 m required displacement b) a= du at -2.3 y

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