A zero-order reaction has a constant rate of 4.90×10−4M/s. If after 50.0 seconds the concentration has dropped to 8.50×10−2M, what was the initial concentration?
if zero roder
RATE = K
RATE = 4.9*10^-4
t = 50 s
then
A = A0 - kt
(8.5*10^-2) = A0 -( 4.9*10^-4) * 50
A0 = (8.5*10^-2) +( 4.9*10^-4) * 50
A0 = 0.1095 M
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