Question

PROBLEM 1. Determine the internal energy of H20 at 10 MPa and 450 °C. Determine the enthalpy of water at a quality of 0.3 and temperature of 300 °C. Determine the specific volume of water at 5 MPa and 1000 °C.

Answer 1

solution :- find internal energy of H₂0 at compa and temperature usic find eathalpy of water at quality of 0.3 and temperature 300c find specific volume of water af 5upa and - Temperature loc wated properties can be calculated by steam table At lompa Tsaf = 311c le tere Tsusic) So, T> Tsat it will be Superheated steam. from the table of super heated steam I UT un h kolleg 72849.2 0.0299 3118 uso | 2956.3 0.33524 3258 500 3056-3 0.036793 3387 Internal ехалу U at loopa At usoc 2956.3 The

say h at x 30.3 To zuc Af Temp suc Sat & Vg of hf hfg ng 8587.9 0.00l4 9 G-121659 133.27 1344.4 1404.8 27496 h at aso.3 hichfta hfg 51344.8 +0:3 (1404-8) Емо Чеч ( = 11160 - 24 Ет (9) of water specific vollenme At supa Tsat = 263.95c So T > Tsat 1000> Tsat it will be superheated from superheated table v hs 900 0.10769 4380.2 7.9619 Ion 0.11715 4628.38.1648 1100 0.12653 0882 8:3566 At lovớc , Supa sp.Udlemme lus 0.1 715 wib ka