Interpret the statement as a differential equation. (Use yp for y' and ypp for y".)
On the graph of y = φ(x), the rate at which the slope changes with respect to x at a point P(x, y) is the negative of the slope of the tangent line at P(x, y).
slope of the tangent at P(x,y)
rate at which slope changes with respect to x at P(x,y)
Interpret the statement as a differential equation. (Use yp for y' and ypp for y".)
Use the substitution x = et to transform the given Cauchy-Euler equation to a differential equation with constant coefficients. (Use yp for dy dt and ypp for d2y dt2 .) x2y'' + 7xy' − 16y = 0 Use the substitution x = ef to transform the given Cauchy-Euler equation to a differential equation with constant coefficients. (Use yp for dy and ypp for dt dt2 x?y" + 7xy' - 16y = 0 x Solve the original equation by solving the...
Use the substitution x = et to transform the given Cauchy-Euler equation to a differential equation with constant coefficients. (Use yp for y dt and ypp for d2y dt2 .) x2y'' − 3xy' + 13y = 4 + 7x Solve the original equation by solving the new equation using the procedure in Sections 4.3-4.5. Use the substitution X = e' to transform the given Cauchy-Euler equation to a differential equation with constant coefficients. (Use yp for- and ypp for t...
Use the substitution x = et to transform the given Cauchy-Euler equation to a differential equation with constant coefficients. (Use yp for dy dt and ypp for d2y dt2 .) x2y'' + 10xy' + 8y = x2 Solve the original equation by solving the new equation using the procedures in Sections 4.3-4.5. y(x) = Use the substitution x = ef to transform the given Cauchy-Euler equation to a differential equation with constant coefficients. (Use yp for dy and ypp for...
Consider the differential equation dy/dx = (y-1)/x. (a) On the axes provided, sketch a slope field for the given differential equation at the nine points indicated. (b) Let y = f (x) be the particular solution to the given differential equation with the initial condition f (3) = 2. Write an equation for the line tangent to the graph of y= f (x) at x = 3. Use the equation to approximate the value of f (3.3). (c) Find the particular solution y...
Consider the differential equation dy dt = t - 2 According to the differential equation, what is the value of y (0)? Question 3 Consider the differential equation dy dt = t - 2 and the given information y(0) = 1. Select the figure that shows the correct graphical representation of y' (O). 0 O 3 y 21 + -2 y 2 1 2 1 2 A z -1 O 3 y 2 X 2. z -1 O 3 2+...
17. Consider the differential equation given by dy/dx = xy/2 (A) On the axes provided, sketch a slope field for the given differential equation. (B) Let f be the function that satisfies the given differential equation. Write an equation for the tangent line to the curve y (x) through the point (1, 1). Then use your tangent line equation to estimate the value of f(1.2) (C) Find the particular solution y=f(x) to the differential equation with the initial condition f(1)=1. Use your solution...
Maple program what are the commands Question6 For the following equation y't y P (0,1) a) Plot the equation with the implicitplot command. Check to see that the given b) Using the implicitdiff command, find a formula for the derivative and find c) point P satisfies the equation the slope at the given point P Use the slope found in part (b) to find an equation for the tangent line to the curve at P. Then plot the equation together...
The variables x and y are implicitly related to the equation x^4+ { ^Y down 1 e^-t^2 dt =1 ( Y is at the top of the { and 1 is at the bottom of the { ) The point p=(1,1) lies on the graph of the equation. Find the slope of the line tangent to the graph at the point p=(1,1) A.) 2e^-2 B.) 2e C.) -4e D.) -4e^-1 E.) 4e^-2
y = 3x0+ QUESTION 2 Solve the given differential equation. (The form of yp is given D2y + 25y = -5 sin 5x (Let y p = Ax sin 5x + Bx cos 5x.) sin 5x + c2 cos 5x + x sin 5x - 1 x cos 5x Oo oo cos 5x + = x cos 5x y = C1 sin 5x + C2 cos 5x + 5x sin 5x y = C1 sin 5x + C2 cos 5x...
Graph the equation and its tangent. a) Graph y = x3 - 4 and the tangent to the curve at the point whose x-coordinate is 0 and the tangent line to the curve at the point whose x-coordinate is 0. b) What is the equation of the tangent line at x = 0 in slope-intercept form (i.e. y = mx+b)?