Homework Answers
speed
of the block when theta = 0
conservation of energy
mgL(1-cosθ) = .5mv^2
v = sqrt[2gL(1-cosθ)]
= sqrt[2*9.8*2.2(1 - cos30)]
= 2.404m/s
speed of the block when theta = -15 degrees
v = sqrt[2gL(cos -15 - cos30)]
= sqrt[2*9.8*2.2* (cos -15 - cos30)]
= 2.075 m/s --> Answer Part C
Tension in the chord at lowest point = mv^2/r + mg
= 0.075*[2.404^2 / 2.2 + 9.8]
= 0.932 N --> Answer Part D
Tension in the chord at θ = 15 degrees = mgcos(15) + mv^2/r
= m*[gcos(15) + v^2/r ]
= 0.075*[9.8*0.966 + 2.075^2 / 2.2 ]
= 0.857 N --> Answer Part E
Tension in the chord at θ = -15 degrees = 0.857 N --> Answer Part F
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