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12. Given the linear transformation defined by 7(x) - Ax and A Find: 0 0 2-3 a. Ker(T) b. Nullity(7) c. Range(7) d. Rank(T)

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Answer #1

Soj & ker(t) = {(x1, x2) IT (24, 12) = 10,0,0), (1, K2) E R²} T(24, X2) = (0,0,0) (1933) 429 + 2 = 0 = x2 =-424 204-3X₂=0 22Da A 4 1 4 0 2 O O 1 0-3 By Rank nullity theorem Renk (Ita) + mullity () = 3 2 - 3 3X2 2x3 Here n=3 2 + nullity (tr) = 3 nul

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