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4. Assume the mass (m -0.045 kg) has a speed of 4.35 m/s at the bottom of the swing (L-0.65 m), how high above the bottom of
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Ajanta Page No. Date [=0.165m r VO ng to Refrenceline V-4.35 m/s many m=0.04519 Apply energy conservation on point 4 2 So is

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