Need to know the same thing for Plant 2 too.
Plant 1
Average cost = C/q = (q4 – 30q3 – 2400q2 + 1,000,000q)/q = q3 – 30q2 – 2400q + 1,000,000
AC is minimized when marginal average cost is 0
dAC/dq = 0
3q2 – 60q – 2400 = 0
q2 – 20q – 800 = 0
It is a quadratic equation with roots q = (20 +/- (400 + 4*800)^0.5)/2 = 40 or -20. The correct value is 40. Hence Plant 1 average cost is minimized at q = 40.
Plant 2
AC = q3 – 45q2 – 3000q + 2,000,000
dAC/dq = 0
3q2 – 90q – 3000 = 0
q2 – 30q – 1000 = 0
It is a quadratic equation with roots q = (30 +/- (900 + 4*1000)^0.5)/2 = 50 or -20. The correct value is 50. Hence Plant 2 average cost is minimized at q = 50.
Need to know the same thing for Plant 2 too. Suppose a firm has two plants...
Please find q= for BOTH plants
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Suppose a firm has two plants with the following costs Plant 1: c, q4-75-5.62542 + 1,000,000q and Plant 2: C2-15q-600q+2,000,000q At what output is the average cost minimized...
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A firm has two independently operated plants that make the same good using the same two inputs. They differ, however, in the technology of production....
The answers I filled are wrong.
1 Suppose that two identical firms produce widgets and that they are the only firms in the market. Their costs are given by C1 = 60Q1 and C2 = 60Q2, where Q1 is the output of Firm 1 and Q2 is the output of Firm 2. Price is determined by the following demand curve: P= 900-Q where Q = Q1 +Q2: Find the Cournot-Nash equilibrium. Calculate the profit of each firm at this equilibrium....
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nvm
dont answer this one
sorry! just need #6!
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