Question

have the lowest first ionization energies of the groups listed. Halogens Alkaline earth metals Transition elements Alkali metals

Answer 1

(1)

The answers is Alkali metals

Alkali metal have only one electron in the outermost orbit and by losing it they get noble gas configuration. So they have lowest first ionization energy.

Halogens requires one electron to complete the octet. So they have very high first I.E.

Alkaline earth metals two electrons in the outermost orbit. So their first I.E. is more then that of alkali metals.

In transition elements d-sub shell is involved so more energy then the alkali metals needed to remove an electron

(2)

The answers is 6

0三):

There are 3 bonds means 6 bonded electrons.

(3)

The answer is HF.

The electronegativity of Florine is more than that of Chlorine. Therefore HF is more polar than HCl.

The Cl2 and F2 are non-polar.
(4)

The answer is (Linear geometry)

BeCl2

has tetrahedral geometry

CH 4

is bent

Н,0

is bent

SCI