(1)
The answers is Alkali metals
Alkali metal have only one electron in the outermost orbit and by losing it they get noble gas configuration. So they have lowest first ionization energy.
Halogens requires one electron to complete the octet. So they have very high first I.E.
Alkaline earth metals two electrons in the outermost orbit. So their first I.E. is more then that of alkali metals.
In transition elements d-sub shell is involved so more energy then the alkali metals needed to remove an electron
(2)
The answers is 6
There are 3 bonds means 6 bonded electrons.
(3)
The answer is HF.
The electronegativity of Florine is more than that of Chlorine. Therefore HF is more polar than HCl.
The Cl2 and F2 are non-polar.
(4)
The answer is (Linear geometry)
has tetrahedral geometry
is bent
is bent
have the lowest first ionization energies of the groups listed. Halogens Alkaline earth metals Transition elements...
complete the sentences regarding alkaline earth metals The Group 2A(2) elements are called alkaline earth metals because their oxides give (alkaline) solutions and melt at such temperatures that they remained as solids ("earths") in the alchemists fires. denser low for 2A metals than larger lower The melting and boiling points are much for the corresponding 1A metals. ences smaller oxidizing Compared to corresponding Group 1A(1) elements, Group 2A(2) elements have metallic bonding and atomic sizes which makes them harder and...