Question

Q5. The magnetization curve for a shunt DC generator is shown in Figure Q5-1.The generator is rated at 6 kW, 120 V, 50 A, and 1800 r/min and is shown in Figure Q5-2. Its field circuit is rated at 5A Figure Q5-1 The following data are known about the machine: 11r 0.180 120 V R, 24 Ω R.-0.18Ω -0 to 30 2 NF #1000 turns per pole v, Figure Q5-2 The shunt field resistor Radj is adjusted to 10 2, and the generator's speed is 1800 r/min. (a) What is the no-load terminal voltage of the generator? (b) Assuming no armature reaction, what is the terminal voltage of the generator with an armature current of 20 A? 40 A? (c) Assuming an armature reaction equal to 200 A turns at full load, what is the terminal voltage of the generator with an armature current of 20 A? 40 A?

part (b)

Answer 1

om the above rng ielizalion cunve,'洳 voltage EAo at 1800 γ/min s 87 v since the ackal ix 100/min The minimum -lod volage 7V b"The maximum voltage will α(un ak coil( α(una土叶ん hishek canenr o Ape of nan minimum volloj* buet cameak o spe . The maximum ponible feld emenk The Cut renk rom the moretisirg curve, thi volkae 20001/min ,→he t800 r/minr&MV no-tood Ea。af sine ackn! Spocells maximum volt, ls 0 lsoo -1 f(min) ら2, 22A. Fro Tha minimem 1O-loodlag s . IS0 1800

Hoor Imin tbomuch feld cunerk genaato The ineinal OA)(0.18)=av vollage about lo6 Aei to Mognalization carue must be auo >80A EA 2 eg TA- SOA 700 800 113V