Homework Answers
The level L such that there is probability only 0.15 that the mean glucose level of 5 test results falls above L is
L = Mean + Z0.15 Sigma / sqrt(n)
= 120 + 1.036 * 15 / sqrt(5)
= 126.9496 = 126.95
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please solve neatly 13.34 Glucose testing, continued. Shelia's measured glucose level one hour after ingesting a...
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please solve neatly
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