Question

1 poin Sheilas measured glucose level one hour after a sugary dnnk vanes according o 0.15 that the mean glucose level of 5 test results falls above L? he Normal ds bution with μ 1 0 m and σ 15 m d what s ele el L such that here s robabil ii

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Answer #1

The level L such that there is probability only 0.15 that the mean glucose level of 5 test results falls above L is

L = Mean + Z0.15 Sigma / sqrt(n)
= 120 + 1.036 * 15 / sqrt(5)
= 126.9496 = 126.95

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