Question

Use these parameters for questions 1-4 A field with an area of 0.10 km? experiences a 20.0 cm snowfall. You determine the SWE to be 25.0%. Use the constants below, assuming they are constant with temperature. All of your answers for energy calculations should be in KJ. Latent heat of vaporization: A = 2.45x10 J kg Latent heat of melting: Am = 3.34x105 J kg Latent heat of sublimation: = 2.83x10° J kg nuom.orf Specific heat capacity of water: C, (water) = 4.184 kl kg K1 Density of water: pw = 1000 kg m3 ulsa of Hehog (d 1) (4 points) Using the dimensions of the snowpack, the SWE, and the density of water, calculate the kilograms of water in the snowpack. r0ot ot 0 mont enuteregn Is of (2nioq S)> isn of yene arli et sw ori asinoqev of yao rlt aelualso of selu (atniog S) ( 2) (3 points) Using the , calculate the energy required for the snowpack to sublimate. of bewone erts sot beniupegnene sris otaluolso of erliegot csigneno eteri: bbA (niog 1) (o ssoque bme tlom

Answer 1

In given question we are required to given answer to various question regarding snow pack energy requirement for melting, sublimation and vaporization.

solution is given below step by step

Cuirem field area A= 0.10 K.m2 = 100000m, Snowfall = 20.06m. - 0,2m · Snow water equivalent (SWE) – 25.0%. Latent heet of veporizatiem lv = 2.45 X1063/kg Latent heat of melting Am = 3.34 x 1055 1kg Latent heet of Serblimilion 15 = 2.83% 706 31kg Specific heat copacity of watery eps 4.184 KJ kg Ik- Density of water Pw = 1000 kg/m3 1 Kilogrom of watey in the snow pack - Volume oh snow pack X SWE X density ofwelery s 105x0.2 x 0.25 X 1000 m = 5.0 x106 kg P Energy required fon the snowpack to Sublimate = mis = 5.0 x 106 xf2.83x106.3 kg) 126 = 1.415 x1olo K5] 3) Now Calculating energy required for the snowpack to meet and then evaporate a) 1 (6) Amount of energy to melt snow - 400°C--- watent visang = mxam = 5x100x 3.34%20S Srow) y ¡ (L+vi L i Pm 3 1.67x109 kJ ..CICE (S+L) L i e amount of energy to raise tempo to loo'c Emm-miplegimu! = map(300-0) (d) Ameemt of energy to vaporize wcalen, I = 5x16x4.184(100) =mx Av = $4106x2.45X105 Qu = 1.225X100 KJ) Qp = 2.092x109 kJ 9 Total energy required =1&mtQp + Qu1.6012 X800 Ks Temperature L ICE+water (L), Energy

100 100 Temperature Energy in kJ - Temperature 1.67E+09 1.88E+09 2.09E+09 2.30E+09 2.51E+09 2.72E+09 2.93E+09 3.13E+09 3.34E+09 3.55E+09 3.76E+09 1.60E+10