2.5 rad/sec = 23.873241491063457 RPM
23.873241491063457 RPM = 1 rotation in 2.5 sec
ω = 2π/ T =2π/ 2.5 = 2.51327 radian /s
Initial angular momentum = 900*2.513
Final angular momentum [900 + 40 *2^2] ω2
Angular momentum is conserved.
[900 + 40 *2^2] ω2 = 900 ω1
ω2 = 900 *2.51327 / [900 + 40 *2^2]
ω2 = 2.134 radian /s
A large turntable rotates about a fixed vertical axis, and has a moment of inertia of...
7) A turntable with moment of inertia IT = 0.042 kg m2 and radius R = 0.24 m is rotating with ω = 0.68 rad/s. A mouse of mass m = 0.053 kg is standing on the edge of the turntable. a) What are the total moment of inertia and the total angular momentum of this system? b) If the mouse walks towards the center of the turntable, does the angular velocity increase or decrease? Explain the answer conceptually. c)...
A turntable has a radius of 0.80 m and a moment of inertia of 2.0 kg m2. The turntable is rotating with an angular velocity of 1.5 rad/s about a vertical axis though its center on frictionless bearings. A very small 0.40-kg ball is projected horizontally toward the turntable axis with a velocity of 3.0 m/s. The ball is caught by a very small and very light cup-shaped mechanism on the rim of the turntable (see figure). a) What is the...
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You are given that the “heart
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We know the heart shaped object has a moment of inertia of I =
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A uniform rod rotates in a horizontal plane about a vertical
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rotation.
Tries 0/5
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10*) The Sun has approximate radius 7×108 m, and rotates around
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need to substitute a value for M). b) Suppose the Sun were to
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1) The parallel axis theorem provides a useful way to calculate the moment of inertia I about an arbitrary axis. The theorem states that I = Icm + Mh2, where Icm is the moment of inertia of the object relative to an axis that passes through the center of mass and is parallel to the axis of interest, M is the total mass of the object, and h is the perpendicular distance between the two axes. Use this theorem and...