A uniform rod rotates in a horizontal plane about a vertical axis through one end. The...
A uniform rod rotates in a horizontal plane about a vertical axis through one end. The rod is 12.00 m long, weighs 20.00 N, and rotates at 350 rev/min clockwise when seen from above. Calculate its rotational inertia about the axis of rotation.
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Calculate the angular momentum of the rod about that axis.
A man stands at the center of a platform that rotates without friction with an angular speed of 1.2 rev/s. His arms are outstretched, and he holds a heavy weight in each hand. The moment of inertia of the man, the extended weights, and the platform is 13.3 kg*m^2. When the man pulls the weights inward toward his body, the moment of inertia decreases to 2.4 kg*m^2.
What is the resulting angular speed of the platform?
41.78 rad/s
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What is the kinetic energy of the system before the man pulls the weights to his body?
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What is the kinetic energy of the system after the man pulls the weights to his body??
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What is the change in kinetic energy of the system?
Homework Answers
Find the mass of the rod using the weight. Use the angular
velocity and moment of inertia to find the angular momentum as
shown below
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This concludes the answers. If there is any mistake or
omission, let me know immediately and I will fix
it....
- 1) a) Weight of nod is, - W = mg => 20N = mg > M= 20N - 20N 9.8m/s2 = 2:04 Kg Izmete mazme = 197.9614 me I = M22 197.96/kg.m2 b) L: Tu 1 50 *2raols) - 3590.4 19.me 60
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