Question

uniform rod of mass 3.30×10−2 kg and length 0.450 m rotates in a horizontal plane about...

uniform rod of mass 3.30×10−2 kg and length 0.450 m rotates in a horizontal plane about a fixed axis through its center and perpendicular to the rod. Two small rings, each with mass 0.250 kg , are mounted so that they can slide along the rod. They are initially held by catches at positions a distance 5.40×10−2 m on each side from the center of the rod, and the system is rotating at an angular velocity 30.0 rev/min . Without otherwise changing the system, the catches are released, and the rings slide outward along the rod and fly off at the ends.

Part A

What is the angular speed of the system at the instant when the rings reach the ends of the rod?

ωsystem = rev/min

Part B

What is the angular speed of the rod after the rings leave it?

ωrod = rev/min
0 0
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Answer #1

= 12 X .250 X (5.40X10- 3.30X10-LX(0.45。 2 4-5 85.568 X/o12 2 2538693 x10-4

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