Question

KHW 03 Electric Potential Problem 11 Part A Determine V-V Express your answer using two significant figures Consider point a which is 62 cm north of a -3.8 C point charge, and point b which is 88 cm west of the charge in (Figure 1). Figure 1 of 1 Units Submit Part EB 62 cm Determine the magnitude of E, -E Express your answer using two significant figures. E, E. Value Units

Answer 1

Solution (A) The expression for the electric potential is ka V = d Substitute 9x10' N-m2/C2 for k, -3.8 uC for q and 62 cm for d wwww. (9x10 Nm2/C2(-3.8 uC)10C 1C 1m (62 cm cm =-55.16x103 V Substitute 9x10° N-m2/C2 for k. -3.8 uC for q and 88 cm for d wwww. (10C (9x10° Nm2/C2(-3.8 uC) 1 uC V; 1m (88 cn 102 cm =-38.86x103 v The value of V,-V is V-V-38.86x 103 V +55.16x103 v =16.3x103 V (B) The expression for the electric field due to the point charge is as follows: E=

Substitute -3.8 uC for Q. 9x10° N-m2 /C2 for k. and 62 cm for d 10C (9x10 N m2/C)(-3.8C)C EL Im (62 cm 102 cm =-88.97x10 NCj Substitute -3.8 uC for Q, 9x10° N-m2 /C2 for k, and 88 cm for d 10C (9x10 N-m2/C2(-3.8 C)C E, 1m (88 cm 10 cm =-44.16x103 N/cî The value of E, -E is E-Ea(44.16x10' V) +(88.97x103 v) 99.3x103 V (C) The direction of the E, - E^ is, -1 e tan = E, 88.97x103 44.16x103 -1 = tan 63.60