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1. Eight bulbs are connected in parallel to a 280 V source by two long leads of total resistance 2.0 12. If 250 mA flows thro

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wrre Total current = 8x0.25A totalresistance of eiruit = - 290 luon but an is resistance of leads. Total resistance of 8 bulb4 200mA of current flows instead of 250m A. Total current = 8x0.2 = 106A Total resistance of circuid = 1/2 - 2008 = 1751 resi

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