Question

Assignment Score: 87% Resources Hint Check Answer < Question 15 of 23 > A laboratory on the concept of static equilibrium uses an apparatus called a force table. The force table consists of a round, level platform marked in degree increments about its circumference. In the center of the table sits a massless ring, to which three strings are tied. Each string is strung over a separate pulley clamped to the edge of the platform, and then tied to a freely-hanging mass, so that each string is under tension and the ring is suspended parallel to the table surface. A mass of m = 0.165 kg is located at 8, = 26.5°, and a second mass of my = 0.227 kg is located at 8, = 279º. Calculate the mass my and the angular position (in degrees) that will balance the system and hold the ring stationary over the center of the platform. about us career privacy policy terms of use contact us help

Answer 1

We know M, 2 0.165 M₂ = 0.227 Weight w = = 0.16589.8 a weigh a 1.617N 0.22789.d 2,22246 N w lets us rotate the table by 26.50 aulicheck use. so that me is at O. & M2 at (279-2615) = 252.50 252.5 - 180 = 72.5 W of south south component of MM & = west component of on a cos (725) W2 0.6689 N win (725) xwe 2 2.1216N substract south component from weigh Mi = 1,617 - 0.6689 2 1.4527N (acting worth) Weight M₂ = 12.1216² +1.45272 = 2.571N. mass M3 = 2.541 = 0.2623. 9.8

Direction - and tan (14524) = 29.47 degree clockwise Now rotate the table back 26.5 26:5+29.47 +90 = 145.970 0.2623 kq or 262.3 grad is where to place the m3 of