Question

Assignment Score: 233/2000 Resources Hint Check Answer Question 19 of 20 > A sample of 5.17 g of liquid 1-propanol, C, H, O, is combusted with 46.5 g of oxygen gas. Carbon dioxide and wat the products Write the balanced chemical equation for the reaction. Physical states are optional. chemical reaction: What is the limiting reactant? O oxygen O 1-propanol How many grams of Co, are released in the reaction? mass of CO, How many grams of the excess reactant remain after the reaction is complete? about us Careers privacy policy terms of use contact us help MacBook Air

Answer 1

The stepwise solution is attached below :

The given reaction is as follows 1.2 C3H₂O(l) + 90₂ (g) 6CO2(g) + 8H2O(l) | This is the balanced equation. - Many of C₂ H₂O → 60.09 g/mol uw Molecular | Mw of O2 → 31.9988 g/mol. - weight. I To mw of CO2 AA-01 g/mol uw of H₂o 18 g/mol In the problem, it is given that - 5:17. q. of I-propanol taken 46.5 ģ of O2 gas taken. No. of moles in 5.17 g 1-propanol = 0.036. moles No. of moles in Abo 5 g = abs modesa 1.453 molen.

nuoriting to the balanced oryution - Moles of or a Moles of impropanol According to reogent supplied ---- Molen of 02 1.153. 17 Moles of i-propanol 0.086 Clearly, I propanol is the limiting reagent; an entive (propanol will be consumed and some inercocted 02 will be left: A Moles of co2 = 6 = 3 Moles of I-propand - Holes of Con = 3x0.086 = 0.258 moles. Amount of CO2 produced = 0.258% 41.01 g = 11.35 g. Molea of O2 used = a. Holes of i-propanol 2 · Moles of Oz used = 40.086 = 0.387 moles. Holes of unused 02 = (1.453 - 0.387) moles: = 7:066 moles Mon of 1.066 moles of Q2 = (1.060* 31.9988) g. = 34:11 g. ang - 0 1-Propanol po the limitting rea gent. © 11.35 g of con produced in the reaction. ☺ 34.11 g of Oz in unregeted reagent.