Question

Assignment Week 1 Part III: For the following project determine: 1. SY of paving asphalt (15%) 2. CY of 8" crushed gravel (10%) 3. LF of concrete curb (10%) SF of slab on grade (SOG) for building pad (10%) 5. SF of sidewalk (10%) 6. SY of landscape area ( assume total lot area is 160*130=20,800 SF or 2311 SY) (15%) 7. # of parking spots (4%) BCT 2770 Estimating Fundamentals

Answer 1

Given K 201 Back portion 771 Parking 51 course asphalt paving over 81 compacted crushed Gravel 20 >k 2010 HE 2010 201 Entry portion Front street figure:-(plan of parking) (1.) Sy of paving asphalt For entry position=20x20'-400 sq feet back portion = 20x11' - 220 sq felt for parking area = 771x60= 4620 sq feet 5240 sq feet (5299) - 582 22 sq yara Total =582.22 SY

(2.) cy of 8" crushed gravel For entry portion =20x20' X0°66=264ft 3 For back portion = 20'xlI' X00661 - 145.2ff3 For parking area=77²x601x0"661 = 3049.2 ft3 3 458.4 ft3 Total (3 458.4 = 128.08CY 27 (31) LF of concrete curb grade Concrete curb will be provided of length = 77' in parking area to protect from vehicle = 77L (43) SF of slab on (SOG) for building paa = 801x40' 3200 sq. feet = 3200 SF (5) SF of side walk Area = 30' x 10' = 300 sq feet = 300S

(6) Sy of landscape area (assume total lot area is 160* 130 = 209 800SF or 2311 Sy). Total area = 160X130=20800 SF Deauctions :- Parking area = 400+220+4620 Builaing area = 80X40 = 3200 side walk = 30X20 = 600 Entry in building = loxis = 150 curb 7781-77 Land scape area =(20800-400-220-4620 3200-600-150-77 - 11533 sq feet 11533 = 1281.44 Sqoyara 9 = 1281044 SY 7) # of parking sports Dvehicle Area where vehicle will be parked =77860 - 4620 sq feet - 46205 F (1620) = - 513.33 SY Answer