24. In the figure, a man pushes on the outside edge of a merry-go-round Merry-go-round with...
a certain merry go round is accelerated uniformly from rest and attains an angular speed of 1.2 rad/s in the first 18 seconds. the force which causes this change in angular speed is 1000 n and applied along the tangential line to the edge of the merry go round. if the radius is equal to 1.5 m what is the moment of inertia of the merry go round?
A play ground merry go round has a radius of 3.0 m and a rotational inertia of 600 kg x m2. A 25 g child pushes and jumps on the edge. it is then spinning at 0.80 rad/s. the child then crawls from the rim to the very center of the merry go round. Now how fast does it spin?
A man of mass 75kg stands at the center of a rotating merry-go-round platform of radius 3.0 m and moment of inertia 920 kgm^2. The platform rotates without friction with angular velocity 2.0 rad/s. The man walks radially to the edge of the platform. Calculate: the angular velocity of the system when the man reaches the edge, and the change in the kinetic energy of the system.
A 3.5 kg cat is near the edge of a 6.5 m diameter merry-go-round in a playground. A man pushes and accelerates the merry-go-round from rest at a uniform rate of 0.75 rad/s2. The cat clings tighter and tighter, but can only hold on with 150 N of force and eventually flies off. At what tangential velocity will the cat fly off? This occurs when the needed centripetal force exceeds what the cat's claws can supply.
17. A 25.0 kg girl stands on the edge of a merry-go-round that is turning with an angular speed of 0.750 rad/s. The merry-go-round has a radius of 2.50 m and a moment of inertia of 200 kg m2. The girl walks to the center of the merry-go-round and stands there. What is the new angular speed of the merry-go-round? (Treat the girl as a point particle.)
Starting at rest, a child applies a 63N force tangent to the edge of a merry-go-round through 31 2 rotations. At that moment, she stops and admires her spinning merry-go-round. Then she jumps onto the edge of the merry-go-round. The girl’s mass is 25kg, the merry-go-round’s moment of inertia is 70kg· m2, and the merrygo-round’s diameter is 2.0m. What is the final angular speed of the girl and merry-go-round? Child applies tangential force. Fan
please help Extra credit (10 points each) 1. A horizontal merry-go-round has a weight of 600-N and radius of 2.00 m. It is started from rest by a constant horizontal force of 50.0 N applied tangentially to the merry-go- round. Treat the merry-go-round as a solid disk. a) What is the moment of inertia of the merry go round, in kg m?? b) What is the angular acceleration (in rad/sec)? c) What is its angular speed after 4.00 seconds (in...
A playground merry-go-round of radius R = 2.20 m has a moment of inertia of I = 280 kgm2 and is rotating at 11.0 rev/min about a frictionless vertical axis. Facing the axle, a 21.0 kg child hops on to the merry-go-round and manages to sit down on its edge. What is the new angular speed of the merry-go-round? 8.04 rad/s 0.845 rad/s 3.17 rad/s 1.18 rad/s 0.445 rad/s
nly the final value of the answer. A merry-go-round with a moment of inertia of 6.78 x 109 kg • m2 is coasting at 2.20 rad/s. When a 87-kg man steps onto the rim, the angular velocity decreases to 20 rad/s. What is the radius in meters of the merry-go-round? Write your answer with ONE decimal place.
need help ASAP please A playground merry-go-round of radius R = 2.10 m has a moment of inertia of I = 260 kgm2 and is rotating at 11.0 rev/min about a frictionless vertical axis. Facing the axle, a 23.0 kg child hops on to the merry-go-round and manages to sit down on its edge. What is the new angular speed of the merry-go-round? O 0.229 rad/s 1.21 rad/s 0.829 rad/s 0.829 rad/s 2.95 rad/s