please help Extra credit (10 points each) 1. A horizontal merry-go-round has a weight of 600-N...
A merry-go-round, which may be approximated as a solid disk of mass 90.0 kg and radius 2.00 m, is originally at rest but free to rotate in the horizontal plane about its center. A child applies an external force of 20.0 N tangentially to the outer edge of the merry-go-round, for a duration of 15.0 s. (a) What is the final angular velocity of the merry-go-round? (b) What is the average power supplied by the child in the process? (c)...
014 10.0 points A horizontal 950 N merry-go-round of radius 11.16 m is started from rest by a constant horizontal force of 51.9 N applied tangentially to the merry-go-round. Find the kinetic energy of the merry-go- round after 3.77 s. The acceleration of gravity is 9.8 m/s2. Assume the merry-go-round is a solid cylinder Answer in units of J.
014 10.0 points A horizontal 973 N merry-go-round of radius 1.93 m is started from rest by a constant horizontal force of 40.9 N applied tangentially to the merry-go-round Find the kinetic energy of the merry-go- round after 3.44 s. The acceleration of gravity is 9.8 m/s2. Assume the merry-go-round is a solid cylinder. Answer in units of J.
A horizontal 810-N merry-go-round of radius 1.60 m is started from rest by a constant horizontal force of 45 N applied tangentially to the merry-go-round. Find the kinetic energy of the merry-go-round after 2.0 s. (Assume it is a solid cylinder. Also assume the force is applied at the outside edge.)
A merry-go-round with moment of inertia 400 kg-m^2 and radius 2.0m is rotating with angular speed 0.50 rad/s in the clockwise direction about a fixed axis. A child of mass 40 kg runs tangentially to the merry-go-round with speed 3.0m/s and grabs onto the outside edge of the merry-go-round. a. What is the final angular velocity of the system (merry-go-round plus child)/ What is the final tangential speed of the child? b. What is the change in kinetic energy? c....
A 90-kg merry-go-round of radius 2.0 m is spinning at a constant speed of 20 revolutions per minute. A kid standing on the ground decides to bring the merry-go-round to rest and applies a force of 10.0 N tangentially to the merry-go-round. If the merry-go-round is modelled as a solid cylinder, (A) calculate its moment of inertia. (B) What is the angular acceleration of the merry-go-round? (C) How many revolutions will the merry-go-round complete until it finally stops? 1) [25...
A horizontal 726 N merry-go-round of radius 1.37 m is started from rest by a constant horizontal force of 55.6 N applied tangentially to the merry-go-round. Find the kinetic energy of the merry-go- round after 2.36 s. The acceleration of gravity is 9.8 m/s^2. Assume the merry-go-round is a solid cylinder. Answer in units of J.
A horizontal 819 N merry-go-round of radius 1.47 m is started from rest by a constant horizontal force of 73.6 N applied tangentially to the merry-go-round. Find the kinetic energy of the merry-goround after 2.21 s. The acceleration of gravity is 9.8 m/s 2 . Assume the merry-go-round is a solid cylinder. Answer in units of J.
A horizontal 810-N merry-go-round of radius 1.40 m is started from rest by a constant horizontal force of 45 N applied tangentially to the merry-go-round. Find the kinetic energy of the merry-go-round after 4.0 s. (Assume it is a solid cylinder. Also assume the force is applied at the outside edge.)
a certain merry go round is accelerated uniformly from rest and attains an angular speed of 1.2 rad/s in the first 18 seconds. the force which causes this change in angular speed is 1000 n and applied along the tangential line to the edge of the merry go round. if the radius is equal to 1.5 m what is the moment of inertia of the merry go round?