Question

I need help in this question. I am trying to apply nulbasis function but it is not working. Please do it in MATLAB and show me so i can do it. I am also showing solution so you can see it.

Here is solution: https://www.chegg.com/homework-help/linear-algebra-and-its-applications-5th-edition-chapter-6.1-problem-34E-solution-9780321982650

E-6 3 6 -5 [M] Let A= | 8 -6 12 -10 14 -21 –27 -33 -13 25 28 14 34 38 18 50 41 23 49 2933 Construct a matrix N whose columns form a basis for Nul A, and construct a matrix R whose rows form a basis for Row A (see Section 4.6 for details). Perform a matrix computation with N and R that illustrates a fact from Theorem 3. Reference Theorem 3: Let A be an mxn matrix. The orthogonal complement of the row space of A is the null space of A, and the orthogonal complement of the column space of A is the null space of AT: (Row A)+ = Nul A and (Col A)+ = Nul AT

Answer 1

given that, [m] tet A- [6 6 I s T 12 14 3 -27 - 33 -13] us a5 28 14. e-6 34 38 18 -10 so ul 23 -21 49 29 33 Type Transform the matrin to the reduced row echtonton TYPE 2) internet the reduced row echion form the Type Transform matrix reduced row echton form this ir rowl Rowl: 'the ole -6 34 38 18 Roo 2: oyu ņ u 20W 3 +63-27 -3 -137 5 7 / 13 6 -5 25 28 14 ) Multiply 6 -5 25 28 14 8 -6 34 38 18 | 12 -10 so 41 23 by 112 10 to 4 23 in 21 na 29 33) - 146 [14 -21 49 29 33 [ 1 2 1 2 13 Jadd-6 time i 7 137 1o5 25-28 14 istrow to lo-2 -2 -5 il 18 -6 34 38 18 | androw 8 - 6 34 38 18 12 -10 50 41 33 | 12 - 10 to 41 23 Li4 -21 49 29 33 [ 14 -21 49 29 83 Tot 13 ] addesting 1 1 - - 2 2 2 2 2 2 0 -2 -2 -5 1st row to 0-2 -2 -5 the god 8 -6 34 38 1 12 -10 50 u 23 (14 -21 49 29 33 [ 1 2 1 2 1 2 137 add-12 0 -2 -2 51 ist row to 0 -2 -2 -6 2 16 4throw ó -2 -2 -6 3 12 10 Jo 41 23 o 4-4-25-3 r14-21 49 29 33 14-21 ur 293 I row qş g sla ſ m/or amar anledala Row u times the

2 -2 -6 دو تازه - ما دربا Isthrow Rows: 1 - 2 2 2 2 2 2 75 add-le times -2 -51 0 -2225" Hwioh rowko 10 -2 lo -2 220를 o U -U -2 bu -4-25J |u -21 -492933 일 데 닐올블 무 muthiple 올 블 Roob the and o -2 -2-51| rouo -222 -6를 I bg-/ o -u U-25-3 대에 0 -4 -14 248일 Rowz 널올블무 g 2 timg the 2nd row 0 -2 du -53 o -u 14 -48 올|32roo Lo 내 tu ug 에이 이 ; 우 이 이 양 - ماه ام راسا بیا داما تاله Lotu u 에는 10 Rows | add u time the and how to o wth row.) 일 올 블뮈 90 에 -907 aldamholm ㅇ 개 개 4-U -2 - 3| LO 1414 -48 add 14 times the and row the 5th row broto Rowa oo - o oo 5 lo oo -13 multiple 3row by -1 매일올끌 몽 이이 올 하 무 무 요 El Timh tm ar fhad to the 내 Row -

Type : Interpret the reduced row ellen rio To - 1 o ! 10 3 which corresponds to the lo 0 o 0 o 0 0 31 0 system dos 2 In Sto! +503 + (-1/3) X5 20. So: bomba 8oo boom nut('/3) u 20 DOOPSIS 00032 of 0 0 OPP. The sytem infintly many solution 75000.0 frapp i 2200 CM, = -543 + (1/3) 45 1.0 TS +1000 M 2 - 113 + [/ur 0. 0 00000 Mga arbitrary y = + (-1/3) vs 22 bodo nsa arbitrary The solution can be writen in the vector form: C8E00 o monoin be oli P.IS. ZE200.- ( hemob.2: bol 32000 320-8- 6 ! set? the null space has a basis formed )