Homework Answers
no of moles of HA = molarity * volume in L
= 0.63*0.0194
= 0.012222moles
no of moles of NaOH = molarity * volume in L
= 0.37*0.0218 = 0.008066moles
----------- HA(aq) + NaOH(aq) --------------> NaA + H2O(l)
I------------ 0.012222---- 0.008066 ------------------ 0
C-------- -0.008066----- -0.008066 ---------------- 0.008066
E--------- 0.004154 -------- 0 ------------------------- 0.008066
PH = PKa + log[NaA]/[HA]
= 4.38 + log0.008066/0.004154
= 4.38 + 0.288
= 4.668 >>>>answer
Add Answer to:
A student is preparing a buffer by mixing a weak acid, HA, with some strong base,...
Titration of Weak Acid with Strong Base A certain weak acid, HA, with a Ka Value of 5.61 *10^-6, is titrated wit...
Titration of Weak Acid with Strong Base A certain weak acid, HA, with a Ka Value of 5.61 *10^-6, is titrated with NaOH. PART A A solution is made by mixing 8.00 mmol(millimoles) of HA and 1.00 mmol of the strong base. What is the resulting pH? express the pH numerically to two decimal places. pH = ? PART B More strong base is added until the equicalence point is reached. What is the pH of this solution at the...
Identifying weak acid values Data A student is trying to identify a weak acid by measuring the pH of partially neutr...
Identifying weak acid values
Data A student is trying to identify a weak acid by measuring the pH of partially neutralized weak acid solutions. In the lab the student is preparing three solutions by adding 5.00 ml, 10.00 ml, and 15.00 mL of a 0.200 M NaOH solution to 10.00 mL of 0.500 M weak acid solution. The solutions are labeled A, B and C below. The student diluted the solutions to 100.0 mL using the deionized water and measured...
Strong base is dissolved in 765 mL of 0.400 M weak acid (Ka = 4.23 ×...
Strong base is dissolved in 765 mL of 0.400 M weak acid (Ka =
4.23 × 10-5) to make a buffer with a pH of 4.19. Assume that the
volume remains constant when the base is added.
Strong base is dissolved in 765 mL of 0.400 M weak acid (Ka 4.23x 10) to make a buffer with a pH of 4.19. Assume that the volume remains constant when the base is added. HA(aq) + OH-(aq) → H2O()-A-(aq) Calculate the pKa...
Strong base is dissolved in 755 mL of 0.400 M weak acid (Kg = 4.71 x...
Strong base is dissolved in 755 mL of 0.400 M weak acid (Kg = 4.71 x 10-5 M) to make a buffer with a pH of 4.10. Assume that the volume remains constant when the base is added. HA(aq) + OH(aq) + H20(1) + A (aq) Calculate the pK, value of the acid and determine the number of moles of acid initially present. pKa = moles of weak acid: mol HA Enter numeric value When the reaction is complete, what...
Strong base is dissolved in 655 mL of 0.600 M weak acid (Ka = 4.06 x...
Strong base is dissolved in 655 mL of 0.600 M weak acid (Ka = 4.06 x 10-5) to make a buffer with a pH of 4.03. Assume that the volume remains constant when the base is added. HA(aq) + OH(aq) > H2O(l) + A (aq) Calculate the pKa value of the acid, and determine the number of moles of acid initially present. pKa = initial amount: mol HA When the reaction is complete, what is the concentration ratio of conjugate...
Tuo UF Weak Acid with Strong Base 5 of 7 > A certain weak acid, HA,...
Tuo UF Weak Acid with Strong Base 5 of 7 > A certain weak acid, HA, with a Ka value of 5.61 x 10 Constants Periodic Table A titration involves adding a reactant of known quantity to a solution of an another reactant while monitoring the equilibrium concentrations. This allows one to determine the concentration of the second reactant. The equation for the reaction of a generic weak acid HA with a strong base is HA(aq) + OH (aq) +...
A buffer is prepared by mixing 200.0 mL of 0.1500 M NaOH with 200.0 mL of...
A buffer is prepared by mixing 200.0 mL of 0.1500 M NaOH with 200.0 mL of 0.200 M Benzoic Acid (a monoprotic carboxylic acid) in a 1-L volumetric flask and then diluted to volume with distilled deionized water. Calculate the pH of the buffer. Ka= 6.28 × 10−5and pKa= 4.01. A. 3.53 B. 4.01 C. 4.49 D. 7.00 E. 11.49
1. Calculation of pH. A weak acid HA (pKa = 4.85) reacted with strong base NaOH The reaction is HA + NAOH H20 + NaA...
1. Calculation of pH. A weak acid HA (pKa = 4.85) reacted with strong base NaOH The reaction is HA + NAOH H20 + NaA. There are 100 mL 0.100 M HA solution, and the concentration of Na OH is 0.100 M. 0 moles a. What is the pH when 0.00 mL of NaOH is added to the 100 mL HA solution? 2 x1 les b. What is the pH when 20.0 mL of NaOH is added to the 100...
Strong base is dissolved in 585 mL of 0.600 M weak acid (Ka=3.46×10−5) to make a...
Strong base is dissolved in 585 mL of 0.600 M weak acid (Ka=3.46×10−5) to make a buffer with a pH of 4.17 Assume that the volume remains constant when the base is added. HA(aq)+OH−(aq)⟶H2O(l)+A−(aq) Calculate the pKa value of the acid, and determine the number of moles of acid initially present. pKa= initial amount: mol HA When the reaction is complete, what is the concentration ratio of conjugate base to acid? [A−]/[HA]= How many moles of strong base were initially...
Question: In the figure below, titration curves for strong acid with strong base and weak acid...
Question: In the figure below, titration curves for strong acid
with strong base and weak acid with strong base are shown. Compare
the shapes of these curves early in the titration for three
different cases: titration of a strong acid, titration of a weak
acid with a lower pKa, and titration of a weak acid with a higher
pKa. Discuss with the class why the titration curve for weak acids
increase more rapidly early in the titration than do stronger...
Identifying weak acid values
Data A student is trying to identify a weak acid by measuring the pH of partially neutralized weak acid solutions. In the lab the student is preparing three solutions by adding 5.00 ml, 10.00 ml, and 15.00 mL of a 0.200 M NaOH solution to 10.00 mL of 0.500 M weak acid solution. The solutions are labeled A, B and C below. The student diluted the solutions to 100.0 mL using the deionized water and measured...
Strong base is dissolved in 765 mL of 0.400 M weak acid (Ka =
4.23 × 10-5) to make a buffer with a pH of 4.19. Assume that the
volume remains constant when the base is added.
Strong base is dissolved in 765 mL of 0.400 M weak acid (Ka 4.23x 10) to make a buffer with a pH of 4.19. Assume that the volume remains constant when the base is added. HA(aq) + OH-(aq) → H2O()-A-(aq) Calculate the pKa...
Strong base is dissolved in 755 mL of 0.400 M weak acid (Kg = 4.71 x 10-5 M) to make a buffer with a pH of 4.10. Assume that the volume remains constant when the base is added. HA(aq) + OH(aq) + H20(1) + A (aq) Calculate the pK, value of the acid and determine the number of moles of acid initially present. pKa = moles of weak acid: mol HA Enter numeric value When the reaction is complete, what...
Strong base is dissolved in 655 mL of 0.600 M weak acid (Ka = 4.06 x 10-5) to make a buffer with a pH of 4.03. Assume that the volume remains constant when the base is added. HA(aq) + OH(aq) > H2O(l) + A (aq) Calculate the pKa value of the acid, and determine the number of moles of acid initially present. pKa = initial amount: mol HA When the reaction is complete, what is the concentration ratio of conjugate...
Tuo UF Weak Acid with Strong Base 5 of 7 > A certain weak acid, HA, with a Ka value of 5.61 x 10 Constants Periodic Table A titration involves adding a reactant of known quantity to a solution of an another reactant while monitoring the equilibrium concentrations. This allows one to determine the concentration of the second reactant. The equation for the reaction of a generic weak acid HA with a strong base is HA(aq) + OH (aq) +...
1. Calculation of pH. A weak acid HA (pKa = 4.85) reacted with strong base NaOH The reaction is HA + NAOH H20 + NaA. There are 100 mL 0.100 M HA solution, and the concentration of Na OH is 0.100 M. 0 moles a. What is the pH when 0.00 mL of NaOH is added to the 100 mL HA solution? 2 x1 les b. What is the pH when 20.0 mL of NaOH is added to the 100...
Question: In the figure below, titration curves for strong acid
with strong base and weak acid with strong base are shown. Compare
the shapes of these curves early in the titration for three
different cases: titration of a strong acid, titration of a weak
acid with a lower pKa, and titration of a weak acid with a higher
pKa. Discuss with the class why the titration curve for weak acids
increase more rapidly early in the titration than do stronger...
Most questions answered within 3 hours.
-
If you’re standing at the bottom of a hill and asked to evaluate
it while being...
asked 10 seconds from now -
A 8.15- g bullet from a 9-mm pistol has a velocity of 366.0 m/s.
It strikes...
asked 1 hour ago -
The outstanding bonds of Alpha Extracts have a yield to maturity
of 7.4 percent and a...
asked 1 hour ago -
The Problem: The Case of the Harmonizing Vacations
Your CEO is exploring partnering with a European...
asked 2 hours ago -
A chemical equation is balanced by adding coefficients in front
of some formulas so that the...
asked 2 hours ago -
From the literature (reference your sources): What are the
lattice parameters of calcite and aragonite? Why...
asked 3 hours ago -
Your system is rejecting the question am asking which is
preceded by a case study. It...
asked 3 hours ago -
3. On January 2, 2000, Larry creates a trust with himself as
trustee. Larry as trustee...
asked 3 hours ago -
A member of the volleyball team spikes the ball. During this
process, she changes the velocity...
asked 3 hours ago -
Are adult gamers less likely to use a gaming console (Xbox,
PlayStation, Wii, etc...) than teen...
asked 4 hours ago -
The University of
Texas recently reported that 43% of college students aged 18-24
would spend their...
asked 4 hours ago -
The length of stay at a specific emergency department in
Phoenix, Arizona, in 2009 had a...
asked 3 hours ago