A 10 kg block slides down a plane orientated at 15-degrees above the horizontal with a constant velocity. What is the coefficient of the kinetic friction between the block and the plane?
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A 10 kg block slides down a plane orientated at 15-degrees above the horizontal with a...
a 10 kg block slides down a frictionless plane oriented at 30-degrees with respect to the horizontal . A) what is the magnitude of the acceleration of the block down the plane? B) what is the normal force between the block and the plane?
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As a 49 N block slides down a plane that is inclined at 29° to the horizontal, its acceleration is 0.79 m/s2, directed up the plane. What is the coefficient of kinetic friction between the block and the plane? it is not .462
A 10 kg block is placed on an inclined plane that is at an angle of 30 degrees with respect to the horizontal. THe coefficient of kinetic friction between the block and the plane is .1. The block is released from rest at 5m above a spring that is also lying on the plane. The spring has a constant of 50 N/m. What is the max compression of the spring?
Figure 1 shows the 5 kg block A slides down the plane with a constant velocity when 0 = 45° a) Draw Free Body Diagram (FBD) and Kinetic Diagram (KD) of block A by showing all the forces. (4 marks) b) Determine the kinetic friction coefficient of the block A. (3 marks) c) Suddenly the handrail was lifted up at B so that the plane angle become e = 60°. Find the acceleration of block A at this instant (3...
a 2.0 kg block is projected down a plane that makes an angle of 20 degrees with an initial kinetic energy of 1.20 J. if the coefficient of kinetic friction between the block and the plane is 0.40, how will the block slide down along the plane before coming to rest?
an 8kb block starts from rest from the top of a plane, inclined at 40 degrees with respect to the horizontal, and slides down at a constant acceleration. if the coefficient of kinetic friction between the block and the plane is 0.35, determine how far the block will travel in 3 seconds.