If there were 60,000 molecules of a tripeptide in 1.0 nanolitre (nl) of solution, what would the tripeptide concentration be?
express your numerical answer in nmoles/L
number of moles= number of molecules/ Avogadro number
Avogadro number= 6.022 10^23
number of moles= 60000/ 6.022 10^23
= 9.9610^-20
1 mole= 10^9 nmoles
9.9610^-20 moles= 9.9610^-2010^9=9.9610^-11 nmoles
1 L= 10^9 nL
so 1 nL= 10^-9 L
concentration= number of nmoles/ volume of the solution in litres
=9.9610^-11 nmoles/10^-9L
= 9.9610^-2 nmoles/L
If there were 60,000 molecules of a tripeptide in 1.0 nanolitre (nl) of solution, what would...
What would the concentration of the resulting glucose solution be if 333 ml of a 30 % (m/v) glucose solution were diluted to a final volume of 1 L with distilled water? Express your answer using one significant figure. IV AED ?
Part A If the diver were to ascend to the surface (where the pressure is 1.0 atm) while holding her breath, to what volume would the air in her lungs expand? (Assume constant temperature.) Express your answer using two significant figures. VAED V2 L Submit Request Answer Exercise 11.36 3 of 15 Review I Constants I Periodic Table A scuba diver with a lung capacity of 5.5 L inhales a lungful of air at a depth of 43 m and...
S V R c) What is the overall charge of the most abundant tripeptide species at neutral pH (pH 7.0)? e) What is the overall charge of the most abundant tripeptide species below pH 1.0? f) What is the overall charge of the most abundant tripeptide species at pH 11.5? b) What are the three-letter abbreviations for the amino acids? S: Ser Arg Val V: R: c) What is the overall charge of the most abundant tripeptide species at neutral...
Consider the following reaction: PCl5(g)⇌PCl3(g)+Cl2(g) a. Initially, 0.62 mol of PCl5 is placed in a 1.0 L flask. At equilibrium, there is 0.20 mol of PCl3 in the flask. What is the equilibrium concentration of PCl5? Express your answer to two significant figures and include the appropriate units. b. What is the equilibrium concentration of Cl2? Express your answer to two significant figures and include the appropriate units. c. What is the numerical value of the equilibrium constant, Kc, for...
Consider a gas of diatomic molecules (moment of inertia I) at an absolute temperature T. If Eg is a ground-state energy and Eex is the energy of an excited state, then the Maxwell-Boltzmann distribution predicts that the ratio of the numbers of molecules in the two states is nexng=e−(Eex−Eg)/kT. The ratio of the number of molecules in the lth rotational energy level to the number of molecules in the ground-state (l=0) rotational level is nln0=(2l+1)e−l(l+1)ℏ2/2IkT. The moment of inertia of...
What is the pH of the buffer solution in question 2 (Recall the values were: 1.0 L buffer of 0.35 M hydrofluoric acid (HF, Ka = 3.5x10-4) and 0.68 M sodium fluoride (NaF)) after 0.052 moles of HCl are added? The answer is NOT 2.65
lab How many molecules of water are you drinking if you were to consume 450mL bottle of H20? 1. What is the volume of water expressed in L and mL? 2. Calculate the mass of water in g (Hint: we did this in week 1) a. Express mass in mg and kg 3. Find/Calculate the molecular weight of water (H20) 4. Calculate how many moles of water are in the bottle (450mL) 5. Calculate how many molecules of water you...
25. What species is/are present in a 1.0 M solution of HNO,?! a) Only HNO2 molecules b) Only HNO, molecules and H2O molecules c) Only H3O, NOions, and H2O molecules d) HNO2 molecules, H3O+ ions, NO, ions, and H2O
What is the pH of the buffer solution in question 2 (Recall the values were: 1.0 L buffer of 0.35 M hydrofluoric acid (HF, Ka = 3.5x10-4) and 0.68 M sodium fluoride (NaF)) after 0.031 moles NaOH are added?
1.0 L of a 1.2 M solution of formic acid (Ka=1.8x10-4) was prepared. What is the pH of this solution? 1.8328 You are correct. Your receipt no. is 162-1608 Previous Tries Enough potassium formate was added to achieve a final potassium formate concentration of 1.7 M (assume the volume does not change). What is the pH of this new solution? 3.8960 You are correct. ceipt no. is 162-6598 Previous Tries 10 mL of 10 M NaOH is added to the...