Mean (X-) = (10.064+ 10.063 + 10.017 +10.049 + 10.020 + 10.025 + 10.045 + 10.008)/8
Mean (X-) = 10.036 ml
Substituting the values in above formula:
We get, s = 0.02
So, Mean of the measurements is:
10.036 mL ± 0.020 mL
95% confidence interval:
10.021 mL - 10.056 mL
Observed interval :
10.036 mL ± 0.020 mL = 10.016 mL - 10.056 mL
Since it contains the 95% confidence interval, we can say that the nominal value of 10.00 mL can be the true volume of the flask.
Yes.
You are checking the accuracy of a volumetric flask marked 10.00 mL. Measurement| Volume (mL) You...
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tically you can open Assignment 1 here 4. A student calibrates a 25-mL pipette by measuring the volume of the water it can transfer. The reading data are shown as follows (unit in mL): 24.75, 24.83, 24.87, 24.91, and 25.32 (a) Is there an outlier at the 95% confidence level? (b) Calculate the coefficient of variation based on the results from part (a) (c) Suppose the standard deviation of the liquid volume is 0.04 mL, how many replicate measurements would...
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please help me answer the other missing part as soon as possible. Thank you I hope they are clear now. Man SA sede of Aused Mass of Medex 1.08 ) Theory of aspirm 2.24.. 1.913 in this? SLE Lased on your ration, whate of reactions Most of the perfody stwing Mas oferecer odeyinced weighing Man offer perfil 0.731 32 Percent yield 1001 Show all cations B. Aspirin Synthesis 1468 f. Mass of SA used (e) g. Volume of AA used...