mass of CaBr2 taken = 19.8 gram , molar mass of CaBr2 = 199.89 gram/mol
no of moles = mass in gram/molar mass substitute values in this formula to find no of moles of CaBr2 used
no of moles of CaBr2 taken = 19.8/199.89 = 0.099 moles CaBr2 taken
volume of solution = 500 ml convert this volume in liter by using following formula
volume in liter = volume in ml/1000 substitute values in this formula
volume of solution in liter = 500/1000 = 0.5 liter
molarity = no of moles/volume in liter , substitute above calculated values in this formula to find molarity
molarity of solution = 0.099/0.5 = 0.198 M
ans molarity of solution is 0.198 molar
CaBr2 is strong electrolyte which dissociate completly in water as given in following reaction
CaBr2 + H2O Ca2+(aq) + 2Br-(aq)
according to dissociation reaction of CaBr2 1 mole of CaBr2 produces 1 mole of Ca2+ therefore molarity of Ca2+ is same as molarity of CaBr2
therefore molarity of Ca2+ = molarity of CaBr2 = 0.198 M
ans concentration of calcium cation is = 0.198 M
CaBr2 is strong electrolyte which dissociate completly in water as given in following reaction
CaBr2 + H2O Ca2+(aq) + 2Br-(aq)
according to dissociation reaction of CaBr2 1 mole of CaBr2 produces 2 moles of Br- therefore molarity of Br- is double than molarity of CaBr2
therefore molarity of Br- = 2 x molarity of CaBr2 = 0.198 x 2 = 0.396 M
ans concentration of bromide anion is = 0.396M
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