Question

class x {

x () {}

private void one () {}

}

public class Y extends x {

Y() {}

private void two () {

one();

}

public static void main (String[] args) {

new Y().two();

}

}

What changes will make this code compile?

a. Adding the public modifier to the declaration of class x

b. Adding the protected modifier to the x() constructor

c. Changing the private modifier on the declaration of the one() method to protected

d. Removing the Y() constructor

e. Removing the private modifier from the two() method

Answer 1

Answer is -->

c. Changing the private modifier on the declaration of the one() method to protected

Reason-->

A private method can be accessed only within the class it has been declared.

Where as a protected method can be accessed within all classes in the same package and also within the subclasses present in other packages.

In the present scenario, Method one is declared as a private method so it can be accessed only within the Class "x". As you can see in class Y method "two" can be accessed within the class "Y", but you cannot access it from class "x".

So, If you declare it as Protected it can be accessed from other classes and the code compiles.

Hope this helps.