Let x be a normally distributed continuous random variable with a mean of 213 and a standard deviation of 17. Determine the value of x such that the area to the left of x is 0.492. Round the solution to two decimal places, if necessary.
solution
Using standard normal table,
P(Z < z) =0.492
= P(Z < z) = 0.492
= P(Z <-0.02 ) = 0.492
z =-0.02 Using standard normal z table,
Using z-score formula
x= z * +
x=-0.02 *17+213
x= 212.66
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