Question

You have been given the task of organizing a poll regarding an upcoming election. The object is to estimate the proportion of

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Answer #1

Solution :

Given that,

a)

\hat p = 0.66

1 - \hat p = 0.34

margin of error = E = 0.04

Z\alpha/2 = 1.96

sample size = n = (Z\alpha / 2 / E)2 * \hat p * (1 - \hat p )

= (1.96 / 0.04)2 * (0.66 * 0.34)

= 539

Required sample size (n) = 539

b)

\hat p = 0.50

1 - \hat p = 0.50

margin of error = E = 0.04

Z\alpha/2 = 1.96

sample size = n = (Z\alpha / 2 / E)2 * \hat p * (1 - \hat p )

= (1.96 / 0.04)2 * (0.50 * 0.50)

= 601

Required sample size (n) = 601

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